Electronic Design: IC 555 Inverter Circuit using Mosfet

Inverter Circuit. - This is one of implementation of 555 IC and Mosfet to build power inverter system. It is only need small component completed to build this electronic circuit that basically component.

The electronic design circuit of IC 555 Inverter using Mosfet is look like in Figure 1 below. Other component used like resistors, transformer, capacitors, and transistor.

Beside we will show you electronic design circuit and component parts need, we also will give you global description about this circuit. So, please enjoy to continue reading this article until finish and get more useful.

Electronic Circuit Design

Figure 1. IC 555 Inverter Circuit using Mosfet (Source: Eleccircuits)

Component Parts

• IC1_______NE555 timer IC__________________________ = 1 pcs.
• Q1________BC549___NPN 40V 0.5A transistors________ = 1 pcs.
• Q2,Q3_____IRF540___N CHANNEL POWER MOSFET, 100V, 27A, TO-220______ = 2 pcs.
• C1,C2_____0.1uF 100V mylar capacitors_____________________________ = 2 pcs.
• R1________ 4.7K 0.5W resistor___________________________________ = 1 pcs.
• R2________120K 0.5W resistor___________________________________ = 1 pcs.
• R3,R4_______1K______”______”______________________________________ = 2 pcs.
• R5________5.6K______”______”______________________________________ = 1 pcs.
• T1________2A 12V__CT__12V transformer_____________________________ = 1 pcs.

Description

The electronic circuit design like in Figure 1 above show you power inverter circuit using IC 555 and Mosfet. 

According Eleccircuits blog mentioned that IC-NE555 timer is a square wave frequency generator output of 50Hz. The frequency is determined with R2-resistor and C1-capacitor which we set is 50Hz output. Then we use both N-type Mosfet IRF540 (Q2,Q3) as Driver a transformer coil (primary winding). The current of Pin 3 of IC1 will flow two ways, first through R3 to gate of Q2 and, second ways will flow to Q1-transistor BC549 as inverter logic form to reverse signal difference first ways. Next current flow to gate of Q3 to also dirver the transformer. Them cause have AC voltage of 220V to 250V as voltage of battery source 12V to 14.4V.

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Electronic Design: Inverter 12V to 220V 100W Circuit by Transistor

Radio Circuit. - This is one of implementation of transistor to build power inverter system. It is only need small component completed to build this electronic circuit that basically component.

The electronic design circuit of Inverter 12V to 220V 100W Circuit by Transistor is look like in Figure 1 below. Other component used like resistors, transformer, capacitors, and diode.

Beside we will show you electronic design circuit and component parts need, we also will give you global description about this circuit. So, please enjoy to continue reading this article until finish and get more useful.

Electronic Circuit Design

Figure 1.  Inverter 12V to 220V 100W Circuit by Transistor (Source: Eleccircuits.com)

Component Parts

• Q1-Q4______BC557___45V 100mA PNP Transistor
• Q5,Q6______BD139___80V 1.5A NPN Transistor
• Q7,Q8______2N3055___100V, 15A, 115W, >2,5MHz NPN transistor
• D1,D2,D3,D4_____1N4148______75V 150mA Diodes
• D5,D6_______1N4007 __1000V 1A Diodes
• R1,R4,R6,R7_________10K___1/2W Resistors tolerance: 5%
• R2,R3___________150K______1/2W Resistors tolerance: 5%
• R5,R6___________ 47K______1/2W Resistors tolerance: 5%
• R9,R12__________ 220 ohms 1/2W Resistors tolerance: 5%
• R10,R13_________ 560 ohms 1/2W Resistors tolerance: 5%
• R11, R14________ 100K ____1/2W Resistors tolerance: 5%
• R15, R16________ 10 ohms__10W Resistors tolerance: 5%
• R17, R18________ 150 ohms_1/2W Resistors tolerance: 5%
• C1,C2___________0.047uF 50V_____Ceramic capacitors
• C3,C4__________0.01uF 50V____Ceramic capacitors
• C5______________1uF 50V_____ Ceramic capacitors
• C6_____________0.1uF 250V____ Ceramic capacitors
• C7_____________0.1uF 50V_____ Ceramic capacitors
• C8____________220uF 25V_______ Electrolytic capacitors
• T1___230V AC primary to 12V-0-12V,2-8A secondary transformer.

Description

The electronic circuit design like in Figure 1 above show you power inverter circuit using transistor. Other component need also that can supply with low voltage DC +12V and ground source to charge this transistors and all system component from power supply built. With this electronic design circuit you can produce 220V from 12V that useful now.

According Eleccircuits blog mentioned thathis circuit is 100 watt power inverter using power transistor 2N3055. It is designed for you that need to use appliances at outdoor or no electrical places. Someone use it in car or the high mountain etc.

The maximum output power of this circuit about 100 watts, it is suitable for a normal lighting (all home lamps), also used for radio, mini TV, stereo or someone use it for.

Let’s look at to both transistors Q1,Q2 will be connected together as the astable multivibrator form. It will generate the output frequency about 100 Hz at the collector lead of Q2. Then this signal will sent to the two frequency divider makes the frequency is reduced down about 50Hz

Cause we don’t design the circuit to directly work at 50 Hz. Because the generating the steady low frequency is very hard.

The output from divider circuit is sent to base of Q5,Q6. To increase current up to drive the output transistors Q7,Q8, then drive the transformer, finally to supply load.

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Electronic Design: 500W Power Inverter Circuit using SG3526-IRFP540

Radio Circuit. - This is one of implementation of IRFP540 to build power inverter system. It is only need small component completed to build this electronic circuit that basically component.

The electronic design circuit of 500W Power Inverter Circuit using SG3526-IRFP540 is look like in Figure 1 below. Other component used like resistors, capacitors, and zener diode.

Beside we will show you electronic design circuit and component parts need, we also will give you global description about this circuit. So, please enjoy to continue reading this article until finish and get more useful.

Electronic Circuit Design

Figure 1. Electronic Design: 500W Power Inverter Circuit using SG3526-IRFP540 (Source: Eleccircuits)

Component Parts

• R1______________15K_______________ = 1 pcs.
• R2______________22K_______________ = 1 pcs.
• R3______________2.7K_______________ = 1 pcs.
• R4______________10K_______________ = 1 pcs.
• R5______________12K_______________ = 1 pcs.
• R6______________4.7K_______________ = 1 pcs.
• R7______________47K_______________ = 1 pcs.
• R8,R22,R23______0.01 ohms / 5W ______ = 3 pcs.
• R9______________1K (PTC)___________ = 1 pcs.
• R10_____________ 8.2 ohms___________ = 1 pcs.
• R11______________16.9K______________ = 1 pcs.
• R12______________33 ohms____________ = 1 pcs.
• R13,R15, R18- R21_ 22 ohms___________ = 6 pcs.
• R14______________ 18 ohms___________ = 1 pcs.
• R16______________ 1K ________________ = 1 pcs.
• R17______________ 470 ohms___________ = 1 pcs.
• C1,C2____________220uF 16V____Electrolytic____= 2 pcs.
• C3,C7,C9,C10_____220nF 50V____Polyester_____= 4 pcs.
• C4______________1uF 50V________Electrolytic____= 1 pcs.
• C5,C6___________33nF 50V_______ Polyester_____= 4 pcs.
• C8___________2.2 uF 50V_______ Polyester_____= 1 pcs.
• D2__________1N4148_____75V 150mA Diodes__= 1 pcs.
• D2__________1N4002_____100V 1A Diodes__= 1 pcs.
• D4__________18V 1W_____Zener Diodes___= 1 pcs.
• D5,D6_______BY299______Didoes__________= 2 pcs.
• IC1_________LM393N____op-amp IC________= 1 pcs.
• IC2_________SG3526N or SG2526N IC______ = 1 pcs.
• Q1-Q6______IRFP540 mosfet______________ = 6 pcs.
• D1_________LED 3 mm red or as you need____ = 1 pcs.
• T1________220V / 12V-0-12V / 40A transformer__ = 1 pcs.
• PCBs,Heat sink, wires and others.

Description

The electronic circuit design like in Figure 1 above show you power inverter circuit using IRFP540. Other component need also that can supply with low voltage DC +12V and ground source to charge this IC and all system component from power supply built. With this electronic design circuit you can produce White / LF noise generator that useful now.

According Eleccircuits blog mentioned that as 200 watts inverter circuit. We use Q1, Q2 is the mosfet acts as a power output. That can withstand currents up to 18A. According to properties listed in the table of Figure 2. If the circuit is fully functional with maximum power of 12V x 18A = 216 watts. But in practice, the circuit should work up, it may be damaged. Therefore, it is designed to operate up to 200 watts.

Since we want the current more than 40A. But the power mosfet single, able to withstand current is 18A, therefore have to be 3 pcs. And When designing a circuit in a push-pull model thus requires a power mosfet 3 pairs.

We have the output current up to 54A which can withstand more demanding than 14A. It is good for the operation of the circuit. Because each power mosfet will not be overburdened. And the heat of the mosfet least, the lifetime of the life circuit.

In Figure 3 is the inverter circuit with a power output Increased at least 2 pairs and use the 12volts 40A transformer, so that the power output 500 watts.

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Electronic Design: Portable Power Inverter Circuit using CD4047 IC

Inverter Circuit. - Although there are many inverter device sold in the market in this time with competitive price, it will nice when you can build your self this device using popular electronic component.

One electronic design circuit to build power inverter look like in Figure 1 below. From this Figure that it is show you the portable power inverter using monostable/astable multivibrator CD4047 IC that popular found in the market this time.

Beside we will show you electronic design circuit and component parts need, we also will give you global description about this circuit. So, please enjoy to continue reading this article until finish and get more useful.

Electronic Circuit Design

Figure 1. Electronic Design: Portable Power Inverter Circuit using CD4047 IC (Source: Electroschematics)

Component Parts

• IC1: CD4047N
• T1, T2: BS170
• T3, T4: BD139 (or D400)
• T5, T6: IRFZ44N
• D1: 1N4007
• C1: 100 uF/25 V
• C2: 47 uF/16 V
• C3: 100 nF/63 V
• C4: 100 nF/400 V~
• R1: 1K2
• R2: 47K (change to 39K for 60 Hz)
• R3, R4: 1K8
• R5, R6: 1K2

Description

The electronic circuit design like in Figure 1 above show you portable power inverter circuit using the major component called with CD4047 IC. In here we can use 12V source to charge this IC. This is IC for the monostable/astable multivibrator.

According Electroschematics blog mentioned that the circuit is built around the monostable/astable multivibrator CD4047 (IC1). The resistor (R2) and capacitor (C3), connected to pins 2 and 3, will decide the frequency of the astable output pulses (here, it is at about 50 Hz). IC1 gives two similar frequency outputs at pins 10 and 11 (phase of the Q and Q signals varies about 180 degrees). The square wave output signals are processed by the two-channel transistor banks (T1-T3-T5 and T2-T4-T6) to drive the power transformer (TR1). In my prototype, TR1 is a 60-VA toroidal transformer with a nominal 12-V rms secondary and 5-A current. I have powered up the inverter with an SMF battery of 12 V close to 7 Ah and successfully powered one 230-V/40-W lightbulb. The efficiency looks promising with neither the MOSFETs nor the transformer getting hotter than warm.

Because the inverter has fatal mains voltages present, it is highly recommended that it be put into a metal enclosure (with adequate vent holes). The largest component is the toroidal transformer, which should be securely mounted to the chassis. A proper (TO-220) heatsink should be used with the FETs (T5-T6). Note that both the upper and lower FETs can be bolted into a single (TO220x2) heatsink plate, provided that they are insulated from each other and from the heatsink plate. 

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