Electronic Design: 500W Power Inverter Circuit using SG3526-IRFP540

Radio Circuit. - This is one of implementation of IRFP540 to build power inverter system. It is only need small component completed to build this electronic circuit that basically component.

The electronic design circuit of 500W Power Inverter Circuit using SG3526-IRFP540 is look like in Figure 1 below. Other component used like resistors, capacitors, and zener diode.

Beside we will show you electronic design circuit and component parts need, we also will give you global description about this circuit. So, please enjoy to continue reading this article until finish and get more useful.

Electronic Circuit Design

Figure 1. Electronic Design: 500W Power Inverter Circuit using SG3526-IRFP540 (Source: Eleccircuits)

Component Parts

• R1______________15K_______________ = 1 pcs.
• R2______________22K_______________ = 1 pcs.
• R3______________2.7K_______________ = 1 pcs.
• R4______________10K_______________ = 1 pcs.
• R5______________12K_______________ = 1 pcs.
• R6______________4.7K_______________ = 1 pcs.
• R7______________47K_______________ = 1 pcs.
• R8,R22,R23______0.01 ohms / 5W ______ = 3 pcs.
• R9______________1K (PTC)___________ = 1 pcs.
• R10_____________ 8.2 ohms___________ = 1 pcs.
• R11______________16.9K______________ = 1 pcs.
• R12______________33 ohms____________ = 1 pcs.
• R13,R15, R18- R21_ 22 ohms___________ = 6 pcs.
• R14______________ 18 ohms___________ = 1 pcs.
• R16______________ 1K ________________ = 1 pcs.
• R17______________ 470 ohms___________ = 1 pcs.
• C1,C2____________220uF 16V____Electrolytic____= 2 pcs.
• C3,C7,C9,C10_____220nF 50V____Polyester_____= 4 pcs.
• C4______________1uF 50V________Electrolytic____= 1 pcs.
• C5,C6___________33nF 50V_______ Polyester_____= 4 pcs.
• C8___________2.2 uF 50V_______ Polyester_____= 1 pcs.
• D2__________1N4148_____75V 150mA Diodes__= 1 pcs.
• D2__________1N4002_____100V 1A Diodes__= 1 pcs.
• D4__________18V 1W_____Zener Diodes___= 1 pcs.
• D5,D6_______BY299______Didoes__________= 2 pcs.
• IC1_________LM393N____op-amp IC________= 1 pcs.
• IC2_________SG3526N or SG2526N IC______ = 1 pcs.
• Q1-Q6______IRFP540 mosfet______________ = 6 pcs.
• D1_________LED 3 mm red or as you need____ = 1 pcs.
• T1________220V / 12V-0-12V / 40A transformer__ = 1 pcs.
• PCBs,Heat sink, wires and others.

Description

The electronic circuit design like in Figure 1 above show you power inverter circuit using IRFP540. Other component need also that can supply with low voltage DC +12V and ground source to charge this IC and all system component from power supply built. With this electronic design circuit you can produce White / LF noise generator that useful now.

According Eleccircuits blog mentioned that as 200 watts inverter circuit. We use Q1, Q2 is the mosfet acts as a power output. That can withstand currents up to 18A. According to properties listed in the table of Figure 2. If the circuit is fully functional with maximum power of 12V x 18A = 216 watts. But in practice, the circuit should work up, it may be damaged. Therefore, it is designed to operate up to 200 watts.

Since we want the current more than 40A. But the power mosfet single, able to withstand current is 18A, therefore have to be 3 pcs. And When designing a circuit in a push-pull model thus requires a power mosfet 3 pairs.

We have the output current up to 54A which can withstand more demanding than 14A. It is good for the operation of the circuit. Because each power mosfet will not be overburdened. And the heat of the mosfet least, the lifetime of the life circuit.

In Figure 3 is the inverter circuit with a power output Increased at least 2 pairs and use the 12volts 40A transformer, so that the power output 500 watts.